GCSE Physics resources

AQA GCSE Forces

Stopping Distance, Reaction Time and Braking

Stopping distance has a reaction stage and a braking stage. Different factors affect each, so name the stage before explaining a change.

AQA 8463AQA 8464 GCSE PhysicsCombined Science: Trilogy FoundationHigher

Subsection scope: Stopping distance, reaction-time factors and braking conditions: both courses and tiers. Braking-force/work estimates: Higher. Stopping-distance graph interpretation: Physics only.

Start here

The revision snapshot

Stopping distance has a reaction stage and a braking stage. Different factors affect each, so name the stage before explaining a change.

By the end, you should be able to:

  • Calculate thinking and stopping distances.
  • Explain reaction-time and road-condition effects.
  • Higher: connect work, braking force and speed.

Before you revise

Diagnostic question

Choose an answer from memory. Your result tells you what to watch for in the guide.

At 15 m/s with a reaction time of 0.80 s, what is thinking distance?

Read the feedback for every option
  1. Distance uses multiplication.
  2. 15 × 0.80 = 12.
  3. This reverses the relationship.
  4. Time and speed cannot be added.

Core revision guide

Learn the model, then use it

Stopping distance has a reaction stage and a braking stage. Different factors affect each, so name the stage before explaining a change.

Reaction time and thinking distance

Scope: 8463 and 8464 · Foundation and Higher

Thinking distance = speed × reaction time. At 20 m/s and 0.70 s it is 14 m. Tiredness, distraction, drugs and alcohol can lengthen reaction time. Typical reaction times are around 0.2–0.9 s. An electronic reaction test measures elapsed time directly; a ruler-drop test compares catch distance, with repeated trials and a common release procedure. Learning and anticipation are limitations to control.

Braking distance and energy

Scope: 8463 and 8464 · Foundation and Higher

Braking distance starts when braking force acts. Friction does work, reducing kinetic energy and increasing thermal stores in brakes, tyres, road and surroundings. Wet/icy roads, worn tyres or faulty brakes can reduce the available braking force and increase distance. The speed effect is common to both tiers. Higher: with fixed mass and braking force, Fs = ½mv² predicts braking distance proportional to v², so doubling speed requires four times the distance in this model.

Put the stages together

Scope: 8463 and 8464 · Foundation and Higher

Stopping distance = thinking + braking distance. Faster speed increases both; longer reaction time only directly increases the thinking stage in an otherwise equal comparison. Physics-only stopping-distance graph tasks and Higher braking-force estimates need their labels. Large deceleration can overheat brakes and increase loss-of-control risk. Road predictions depend on actual conditions rather than a universal memorised distance.

Stopping distance separates thinking distance before braking from braking distance after brake application.
Both courses: identify which stage each factor changes.Open the full-size exam diagram
Thinking distances = vtm, m/s, s
Stopping distancestopping = thinking + brakingm

Misconception clinic

Replace the tempting answer

Read each belief, say what is wrong with it, then compare your correction.

Tempting idea: 18.75 m.

Use instead: Distance uses multiplication. 15 × 0.80 = 12.

Tempting idea: Longer reaction time only.

Use instead: Reaction time changes thinking distance. Less braking force means more distance to remove kinetic energy.

Retrieval practice

Quick checks

1. Which directly increases braking distance at the same initial speed and reaction time?

Read the feedback for every option
  1. Reaction time changes thinking distance.
  2. Less braking force means more distance to remove kinetic energy.
  3. Earlier detection changes available distance.
  4. That shortens thinking distance.

Worked examples

See the method being built

Apply reaction time and thinking distance in the worked reasoning, then try the changed-context questions below.

Example 1 · Two stages, one total

Scope: 8463 and 8464 · Foundation and Higher

A car travels at 20 m/s with reaction time 0.70 s and braking distance 35 m. Find stopping distance.

  1. Thinking distance = 20 × 0.70 = 14 m.
  2. Keep the separately supplied braking distance of 35 m.
  3. Add 14 + 35.
Show the answer

Stopping distance is 49 m.

Exam precision

Use the physics precisely

Do this: Identify the stage each factor changes. State the fixed-force assumption before using energy to compare braking distances.

Independent practice

Exam-style questions

Write an answer before opening the marking guidance. Then edit the exact phrase or step that would gain the next mark.

1. A car travels at 18 m/s. Reaction time is 0.75 s and braking distance is 24 m. Calculate stopping distance.

[3 marks]

Scope: 8463 and 8464 · Foundation and Higher

Show marking guidance and model answer

Original PhysicsUK mark scheme: Point 1 (1 mark): Thinking distance = vt; stopping = thinking + braking. Point 2 (1 mark): Thinking = 18 × 0.75 = 13.5 m; stopping = 13.5 + 24. Point 3 (1 mark): Stopping distance = 37.5 m. Award each distinct point once. Accept equivalent scientifically correct wording. No half marks.

  1. Thinking distance = vt; stopping = thinking + braking. (1 mark)
  2. Thinking = 18 × 0.75 = 13.5 m; stopping = 13.5 + 24. (1 mark)
  3. Stopping distance = 37.5 m. (1 mark)

Model answer: Thinking distance = vt; stopping = thinking + braking. Thinking = 18 × 0.75 = 13.5 m; stopping = 13.5 + 24. Stopping distance = 37.5 m.

Acceptable answers: Expected result: Stopping distance = 37.5 m. Accept the unrounded value or a correctly rounded equivalent to two or more significant figures; accept equivalent units if converted correctly. No additional measurement interval is implied.

Marking notes: Method marks remain available after an arithmetic error. Carry an earlier numerical error into a later valid step; award that method point if the unit conversion and physics are correct. A fully correct answer with unit earns all marks unless working is expressly requested.

2. Higher: explain why doubling speed may quadruple braking distance if braking force and mass are unchanged.

[2 marks]

Scope: 8463 and 8464 · Higher only

Show marking guidance and model answer

Original PhysicsUK mark scheme: Point 1 (1 mark): Kinetic energy ½mv² becomes four times as large. Point 2 (1 mark): Work done by the same force is Fs, so four times the energy needs four times the distance. Award each distinct point once. Accept equivalent scientifically correct wording. No half marks.

  1. Kinetic energy ½mv² becomes four times as large. (1 mark)
  2. Work done by the same force is Fs, so four times the energy needs four times the distance. (1 mark)

Model answer: Doubling speed quadruples kinetic energy. The same braking force must act through four times the distance to remove it.

Useful next steps

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