GCSE Physics resources

AQA GCSE Waves

Sound, Ultrasound and the Ear

Sound moves through vibrating matter. Ultrasound and seismic evidence use the travel, reflection and transmission of vibrations to infer hidden boundaries.

AQA 8463 GCSE Physics Higher

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The revision snapshot

Sound moves through vibrating matter. Ultrasound and seismic evidence use the travel, reflection and transmission of vibrations to infer hidden boundaries.

By the end, you should be able to:

  • Explain sound conversion in the ear and hearing limits.
  • Calculate an ultrasound boundary distance.
  • Use P- and S-wave evidence to infer a liquid core.

Before you revise

Diagnostic question

Choose an answer from memory. Your result tells you what to watch for in the guide.

An ultrasound echo returns after 200 µs at 1500 m/s. What is boundary depth?

Read the feedback for every option
  1. 0.30 m is the round-trip distance.
  2. 1500 × 0.000200/2 = 0.15 m.
  3. This uses 0.020 s.
  4. The time conversion is grossly wrong.

Core revision guide

Learn the model, then use it

Sound moves through vibrating matter. Ultrasound and seismic evidence use the travel, reflection and transmission of vibrations to infer hidden boundaries.

Ear and hearing limits

Scope: 8463 Physics only · Higher only

Alternating pressure in air makes the eardrum vibrate. Vibrations transfer through middle-ear bones into inner-ear fluid, where sensory structures convert them to nerve signals. This conversion has a limited frequency response; normal human hearing is roughly 20 Hz to 20 kHz. Ultrasound is above 20 kHz. Larger amplitude gives stronger vibration/loudness; higher frequency gives higher pitch.

Ultrasound echo timing

Scope: 8463 Physics only · Higher only

A pulse partly reflects at boundaries between materials. The time records the outward and return journeys: depth d = vt/2. In tissue at 1500 m/s, a 200 microsecond echo gives 1500 × 200 × 10⁻⁶/2 = 0.15 m, a plausible 15 cm depth. An echo time of 0.020 s would imply 15 m, which is unsuitable as an ordinary tissue-depth example.

Seismic waves reveal the core

Scope: 8463 Physics only · Higher only

Earthquakes produce longitudinal P waves that travel through solids and liquids and transverse S waves that cannot pass through liquids. Observed S-wave absence and refracted P-wave paths supply evidence for a liquid outer core and hidden internal boundaries. These are conclusions from wave data, not direct photographs of the core.

Ordered particles are closely spaced in labelled compressions and widely spaced in the labelled rarefaction; particle vibration is parallel to sound travel.
A longitudinal sound snapshot: particles vibrate locally while the disturbance travels.Open the full-size exam diagram
Wave speedv = fλm/s, Hz, m

Misconception clinic

Replace the tempting answer

Read each belief, say what is wrong with it, then compare your correction.

Tempting idea: 0.30 m.

Use instead: 0.30 m is the round-trip distance. 1500 × 0.000200/2 = 0.15 m.

Tempting idea: All waves must stop at every boundary.

Use instead: P waves may transmit and refract. Transmission property connects observation to structure.

Retrieval practice

Quick checks

1. Why does the absence of S waves through part of Earth indicate liquid material?

Read the feedback for every option
  1. Transmission property connects observation to structure.
  2. P waves may transmit and refract.
  3. P waves do pass through liquids.
  4. The detected waves originate at earthquakes.

Worked examples

See the method being built

Apply ear and hearing limits in the worked reasoning, then try the changed-context questions below.

Example 1 · Plausible medical echo

Scope: 8463 Physics only · Higher only

A 200 µs tissue echo travels at 1500 m/s. Find depth.

  1. Convert 200 µs to 0.000200 s.
  2. Find the round-trip distance: 1500 × 0.000200 = 0.30 m.
  3. Halve it and check the body scale.
Show the answer

Depth = 0.15 m = 15 cm, plausible for a tissue boundary.

Exam precision

Use the physics precisely

Do this: Follow the vibration chain or evidence chain requested. For ultrasound echoes use half the travelled distance to locate the reflecting boundary.

Independent practice

Exam-style questions

Write an answer before opening the marking guidance. Then edit the exact phrase or step that would gain the next mark.

1. An ultrasound pulse returns from a tissue boundary after 160 µs. Wave speed is 1500 m/s. Calculate boundary distance.

[3 marks]

Scope: 8463 Physics only · Higher only

Show marking guidance and model answer

Original PhysicsUK mark scheme: Point 1 (1 mark): d = vt/2 because the path is out and back. Point 2 (1 mark): t = 160 × 10⁻⁶ s; d = 1500 × 0.000160/2. Point 3 (1 mark): d = 0.12 m = 12 cm. Award each distinct point once. Accept equivalent scientifically correct wording. No half marks.

  1. d = vt/2 because the path is out and back. (1 mark)
  2. t = 160 × 10⁻⁶ s; d = 1500 × 0.000160/2. (1 mark)
  3. d = 0.12 m = 12 cm. (1 mark)

Model answer: d = vt/2 because the path is out and back. t = 160 × 10⁻⁶ s; d = 1500 × 0.000160/2. d = 0.12 m = 12 cm.

Acceptable answers: Expected result: d = 0.12 m = 12 cm. Accept the unrounded value or a correctly rounded equivalent to two or more significant figures; accept equivalent units if converted correctly. No additional measurement interval is implied.

Marking notes: Method marks remain available after an arithmetic error. Carry an earlier numerical error into a later valid step; award that method point if the unit conversion and physics are correct. A fully correct answer with unit earns all marks unless working is expressly requested.

2. Describe how sound reaches the brain through the ear.

[3 marks]

Scope: 8463 Physics only · Higher only

Show marking guidance and model answer

Original PhysicsUK mark scheme: Point 1 (1 mark): Air pressure variations make the eardrum vibrate. Point 2 (1 mark): Vibration is transmitted through middle-ear structures to inner-ear fluid/sensory cells. Point 3 (1 mark): Sensory structures convert vibration into nerve signals interpreted as sound. Award each distinct point once. Accept equivalent scientifically correct wording. No half marks.

  1. Air pressure variations make the eardrum vibrate. (1 mark)
  2. Vibration is transmitted through middle-ear structures to inner-ear fluid/sensory cells. (1 mark)
  3. Sensory structures convert vibration into nerve signals interpreted as sound. (1 mark)

Model answer: Pressure variations vibrate the eardrum; the vibration reaches the inner ear, whose sensory structures produce nerve signals.

Questions pupils ask

Sound, Ultrasound and the Ear FAQs

Why divide an ultrasound echo distance by two?

The measured delay includes travel to the reflecting boundary and back, so speed times time is twice the one-way depth.

Useful next steps

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