GCSE Physics resources

AQA GCSE Energy

Efficiency and Unwanted Energy Transfers

Efficiency compares the useful output with the total input; it does not measure how quickly a device works.

AQA 8463AQA 8464 GCSE PhysicsCombined Science: Trilogy FoundationHigher

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The revision snapshot

Efficiency compares the useful output with the total input. An efficiency improvement must name the unwanted transfer and the design change that reduces its rate, such as lubrication reducing friction or insulation reducing heating.

By the end, you should be able to:

  • Explain efficiency and dissipation.
  • Apply the energy model, evidence or method to an unfamiliar exam context.
  • Recognise and correct this wrong turn: Putting total input on the top of the fraction.

Before you revise

Diagnostic question

Choose an answer from memory. Your result tells you what to watch for in the guide.

Efficiency is calculated using…

Core revision guide

Learn the model, then use it

Efficiency and Unwanted Energy Transfers questions become manageable when the central model, evidence and exam method are kept together. Read the explanation, test the misconception and then apply the idea without looking back.

Efficiency and dissipation

Efficiency compares the useful output with the total input. An efficiency improvement must name the unwanted transfer and the design change that reduces its rate, such as lubrication reducing friction or insulation reducing heating.

Build the physics picture

Useful energy transfer is not the same as all energy transfer. A motor can give a useful kinetic output while heating its surroundings through friction. Improving efficiency means reducing a named unwanted pathway, not claiming that the input energy has disappeared.

The relationship for this guide

Efficiency: efficiency = useful output ÷ total input (decimal or percentage). Choose each relationship from the physical change described, convert quantities into compatible units and keep the unit beside the final answer.

A 100 joule input splits into 60 joules of useful transfer and 40 joules dissipated to thermal stores.
The useful and dissipated arrows add to the 100 J input, so the efficiency is 60%.Open the full-size exam diagram
Efficiencyefficiency = useful output ÷ total inputdecimal or percentage

Misconception clinic

Replace the tempting answer

Read each belief, say what is wrong with it, then compare your correction.

Tempting idea: Putting total input on the top of the fraction.

Use instead: Efficiency compares the useful output with the total input. An efficiency improvement must name the unwanted transfer and the design change that reduces its rate, such as lubrication reducing friction or insulation reducing heating.

Tempting idea: Mixing a decimal efficiency with a percentage.

Use instead: Useful energy transfer is not the same as all energy transfer. A motor can give a useful kinetic output while heating its surroundings through friction. Improving efficiency means reducing a named unwanted pathway, not claiming that the input energy has disappeared.

Tempting idea: Saying unwanted energy disappears.

Use instead: State the equation, identify useful and total values, give a percentage if requested, then explain the unwanted pathway in words.

Retrieval practice

Quick checks

1. A device is 0.80 efficient. What percentage is this?

2. Which change can improve a bicycle chain’s efficiency?

3. Why is 120% efficiency impossible?

4. Which is the strongest explanation of dissipation?

5. Which value is the total input in an efficiency calculation?

Explore the relationship

Efficiency and dissipation explorer

Change the efficiency or total input. The bar length represents the total input, and its sections show useful and unwanted transfers.

What to notice: use the readout to describe how one variable changes when the other is controlled.

Worked examples

See the method being built

These examples expose the difference between a secure efficiency and dissipation method and the common error “Putting total input on the top of the fraction.”.

Example 1 · Efficiency from energy

A motor receives 500 J and gives 350 J of useful kinetic energy. Calculate efficiency.

  1. Write useful output ÷ total input.
  2. Calculate 350 ÷ 500.
  3. Convert if a percentage is requested.
Show the answer

Efficiency = 0.70 = 70%.

Example 2 · Improving a house

Explain how loft insulation reduces unwanted energy transfer.

  1. Name the unwanted pathway.
  2. State what the insulation changes.
  3. Link to the thermal store of the surroundings.
Show the answer

Insulation reduces energy transfer by heating through the roof, so the house’s thermal energy is transferred to the surroundings more slowly.

Example 3 · Power efficiency

A pump takes 200 W and provides 150 W of useful output. Calculate its efficiency.

  1. Use powers because both values are rates.
  2. Calculate 150 ÷ 200.
  3. Give decimal or percentage.
Show the answer

Efficiency = 0.75, or 75%.

Exam precision

Exam technique: Efficiency and dissipation

Do this: State the equation, identify useful and total values, give a percentage if requested, then explain the unwanted pathway in words.

Independent practice

Exam-style questions

Write an answer before opening the marking guidance. Then edit the exact phrase or step that would gain the next mark.

1. A lamp transfers 24 J usefully from a 40 J input. Calculate efficiency.

[3 marks]
Show marking guidance and model answer

Marking guidance: Award one mark for the correct relationship, one for a valid substitution and one for the final answer with its unit.

Model answer: 24 ÷ 40 = 0.60, so 60%.

2. A machine is 35% efficient. State what happens to the other 65% of the input energy.

[2 marks]
Show marking guidance and model answer

Marking guidance: 2 marks are available for relevant, linked physics points that match the model answer.

Model answer: It is transferred through unwanted pathways, usually to thermal stores of the machine and surroundings.

3. Explain why oil in an engine can improve efficiency.

[3 marks]
Show marking guidance and model answer

Marking guidance: Award up to 3 marks for distinct physics points joined into a clear cause-and-effect chain.

Model answer: It reduces friction, reducing unwanted transfer to thermal stores.

4. A device receives 80 W and provides 20 W useful power. Calculate its efficiency.

[3 marks]
Show marking guidance and model answer

Marking guidance: Award one mark for the correct relationship, one for a valid substitution and one for the final answer with its unit.

Model answer: 20 ÷ 80 = 0.25, or 25%.

5. Give one reason an electric motor can never be 100% efficient in normal use.

[1 mark]
Show marking guidance and model answer

Marking guidance: Award one mark for the precise statement shown in the model answer.

Model answer: Some energy is transferred to thermal stores by electrical resistance or friction.

6. Correct this statement: “The wasted energy has been destroyed.”

[2 marks]
Show marking guidance and model answer

Marking guidance: 2 marks are available for relevant, linked physics points that match the model answer.

Model answer: It has been transferred to less useful stores, not destroyed.

Questions pupils ask

Efficiency and Unwanted Energy Transfers FAQs

What is the main idea in Efficiency and Unwanted Energy Transfers?

Efficiency compares the useful output with the total input. An efficiency improvement must name the unwanted transfer and the design change that reduces its rate, such as lubrication reducing friction or insulation reducing heating.

What mistake should I avoid in Efficiency and Unwanted Energy Transfers?

Putting total input on the top of the fraction. Useful energy transfer is not the same as all energy transfer. A motor can give a useful kinetic output while heating its surroundings through friction. Improving efficiency means reducing a named unwanted pathway, not claiming that the input energy has disappeared.

Useful next steps

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