GCSE Physics resources

AQA GCSE Magnetism and electromagnetism

Transformers and the National Grid

The National Grid’s purpose is common course content. Both courses Higher use ideal-transformer power equality; transformer construction, induction and turns ratio are Physics Higher.

AQA 8463AQA 8464 GCSE PhysicsCombined Science: Trilogy FoundationHigher

Subsection scope: National Grid and efficient transmission: both courses, both tiers. Ideal-transformer power equality: both courses Higher. Transformer mechanism and turns ratio: Physics Higher only.

Start here

The revision snapshot

The National Grid’s purpose is common course content. Both courses Higher use ideal-transformer power equality; transformer construction, induction and turns ratio are Physics Higher.

By the end, you should be able to:

  • Explain high-voltage transmission through the Grid.
  • Higher: use ideal-transformer power equality.
  • Physics Higher: explain transformer action and turns ratio.

Before you revise

Diagnostic question

Choose an answer from memory. Your result tells you what to watch for in the guide.

For the same power sent through the same cables, higher voltage gives…

Read the feedback for every option
  1. P = VI requires lower I when V rises.
  2. This is the Grid efficiency chain.
  3. Cable resistance remains.
  4. Transformers do not create energy.

Core revision guide

Learn the model, then use it

The National Grid’s purpose is common course content. Both courses Higher use ideal-transformer power equality; transformer construction, induction and turns ratio are Physics Higher.

National Grid and high-voltage transfer

Scope: 8463 and 8464 · Foundation and Higher

The Grid links generators and consumers through cables and transformers. Step-up transformers raise transmission voltage; step-down transformers lower it for users. At fixed transmitted power P = VI, raising V lowers I. For the same cable resistance, Pheat = I²R then decreases. Raising voltage is useful for efficient transmission but requires insulation and step-down stages for use.

Transformer mechanism

Scope: 8463 Physics only · Higher only

An alternating current in the primary coil creates a changing magnetic field in an iron core. This changing field reaches the secondary and induces p.d. A steady direct current creates no continuously changing field, so no continuous secondary output. Vₛ/Vₚ = Nₛ/Nₚ; the larger-turn coil has the larger p.d. The iron core links fields and is easily magnetised.

Ideal-transformer power and current

Scope: 8463 and 8464 · Higher only

For an ideal transformer, VₚIₚ = VₛIₛ. Both Physics and Trilogy Higher use this equality. Stepping voltage up steps current down for equal power. If input is 12 V and secondary output is 6 V at 0.50 A, output power is 3 W and ideal primary current is 3/12 = 0.25 A. No turns data are needed for this calculation. Real transformers have losses, so input power exceeds output.

A step-up transformer on a closed iron core obeys the turns ratio before high-voltage transmission and step-down.
A higher transmission voltage gives a lower current for the same power, reducing heating losses in cables.Open the full-size exam diagram
Shared: transmitted powerP = VIW, V, A
Physics Higher: turns ratioVs/Vp = Ns/NpV; turns
Both courses Higher: ideal transformerVpIp = VsIsW

Misconception clinic

Replace the tempting answer

Read each belief, say what is wrong with it, then compare your correction.

Tempting idea: Higher current and more heating.

Use instead: P = VI requires lower I when V rises. This is the Grid efficiency chain.

Tempting idea: 96 V.

Use instead: That reverses the turns ratio. 24 × 100/400 = 6.

Retrieval practice

Quick checks

1. Physics Higher: Np = 400, Ns = 100 and Vp = 24 V. What is ideal Vs?

Read the feedback for every option
  1. That reverses the turns ratio.
  2. 24 × 100/400 = 6.
  3. 4 is the turns-ratio factor, not voltage.
  4. 0.25 is the ratio, which must multiply 24.

Explore the relationship

Transformer turns-ratio model

Change primary voltage or the secondary:primary turns ratio, then use Vₛ = Vₚ × (Nₛ ÷ Nₚ).

Model scope: 8463 Physics only · Higher only

What to notice: use the readout to describe how one variable changes when the other is controlled.

Worked examples

See the method being built

Apply national grid and high-voltage transfer in the worked reasoning, then try the changed-context questions below.

Example 1 · Turns ratio

Scope: 8463 Physics only · Higher only

Primary: 200 turns, 230 V. Secondary: 1000 turns. Find secondary p.d.

  1. Use Vs/Vp = Ns/Np.
  2. Ratio = 1000/200 = 5.
  3. Multiply 230 by 5.
Show the answer

Vs = 1150 V.

Example 2 · Grid loss

Scope: 8463 and 8464 · Foundation and Higher

Explain why the Grid transmits at high voltage.

  1. Use P = VI.
  2. For fixed power, high V means low I.
  3. Link low I to less heating loss.
Show the answer

Lower current reduces energy transferred to thermal stores of cables due to resistance.

Example 3 · AC requirement

Scope: 8463 Physics only · Higher only

Explain why a transformer does not work on steady d.c.

  1. Transformer needs changing magnetic field.
  2. Steady d.c. makes constant field.
  3. No induced secondary p.d.
Show the answer

A steady current does not continually change the magnetic field, so no continuous p.d. is induced in the secondary coil.

Exam precision

Use the physics precisely

Do this: For Grid losses hold transmitted power and cable resistance fixed. Check the course label before using power equality or the Physics turns ratio.

Independent practice

Exam-style questions

Write an answer before opening the marking guidance. Then edit the exact phrase or step that would gain the next mark.

1. Explain why the National Grid uses high transmission voltage.

[3 marks]

Scope: 8463 and 8464 · Foundation and Higher

Show marking guidance and model answer

Original PhysicsUK mark scheme: Point 1 (1 mark): For fixed power, P = VI means higher V permits lower I. Point 2 (1 mark): Lower I reduces heating loss in the same resistive cables. Point 3 (1 mark): Step-down transformers then reduce voltage for consumers. Award each distinct point once. Accept equivalent scientifically correct wording. No half marks.

  1. For fixed power, P = VI means higher V permits lower I. (1 mark)
  2. Lower I reduces heating loss in the same resistive cables. (1 mark)
  3. Step-down transformers then reduce voltage for consumers. (1 mark)

Model answer: High voltage lowers current for the required power and reduces cable heating. Step-down transformers make the voltage suitable for consumers.

2. Physics Higher: a transformer has 600 primary turns, 150 secondary turns and 12 V input. Find ideal secondary p.d.

[3 marks]

Scope: 8463 Physics only · Higher only

Show marking guidance and model answer

Original PhysicsUK mark scheme: Point 1 (1 mark): Vs/Vp = Ns/Np. Point 2 (1 mark): Vs = 12 × 150/600. Point 3 (1 mark): Vs = 3.0 V. Award each distinct point once. Accept equivalent scientifically correct wording. No half marks.

  1. Vs/Vp = Ns/Np. (1 mark)
  2. Vs = 12 × 150/600. (1 mark)
  3. Vs = 3.0 V. (1 mark)

Model answer: Vs/Vp = Ns/Np. Vs = 12 × 150/600. Vs = 3.0 V.

Acceptable answers: Expected result: Vs = 3.0 V. Accept the unrounded value or a correctly rounded equivalent to two or more significant figures; accept equivalent units if converted correctly. No additional measurement interval is implied.

Marking notes: Method marks remain available after an arithmetic error. Carry an earlier numerical error into a later valid step; award that method point if the unit conversion and physics are correct. A fully correct answer with unit earns all marks unless working is expressly requested.

3. Higher: an ideal transformer has 12 V primary p.d. and 6 V secondary p.d. with 0.50 A secondary current. Calculate primary current.

[3 marks]

Scope: 8463 and 8464 · Higher only

Show marking guidance and model answer

Original PhysicsUK mark scheme: Point 1 (1 mark): VpIp = VsIs; Ip = VsIs/Vp. Point 2 (1 mark): Ip = 6 × 0.50/12. Point 3 (1 mark): Ip = 0.25 A. Award each distinct point once. Accept equivalent scientifically correct wording. No half marks.

  1. VpIp = VsIs; Ip = VsIs/Vp. (1 mark)
  2. Ip = 6 × 0.50/12. (1 mark)
  3. Ip = 0.25 A. (1 mark)

Model answer: VpIp = VsIs; Ip = VsIs/Vp. Ip = 6 × 0.50/12. Ip = 0.25 A.

Acceptable answers: Expected result: Ip = 0.25 A. Accept the unrounded value or a correctly rounded equivalent to two or more significant figures; accept equivalent units if converted correctly. No additional measurement interval is implied.

Marking notes: Method marks remain available after an arithmetic error. Carry an earlier numerical error into a later valid step; award that method point if the unit conversion and physics are correct. A fully correct answer with unit earns all marks unless working is expressly requested.

Questions pupils ask

Transformers and the National Grid FAQs

Why are transformers used before electricity enters long cables?

Raising voltage lowers current for the same transmitted power, reducing resistive I²R heating of the cables.

Useful next steps

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