GCSE Physics resources

AQA GCSE Forces

Momentum, Conservation and Safety

Momentum is mass × velocity and is conserved in a closed system. Safety features reduce force by increasing collision time or reducing the change in momentum experienced by a person.

AQA 8463AQA 8464 GCSE PhysicsCombined Science: Trilogy FoundationHigher

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The revision snapshot

Momentum is mass × velocity and is conserved in a closed system. Safety features reduce force by increasing collision time or reducing the change in momentum experienced by a person.

By the end, you should be able to:

  • Track momentum in collisions.
  • Apply the forces model, evidence or method to an unfamiliar exam context.
  • Recognise and correct this wrong turn: Forgetting direction/signs.

Before you revise

Diagnostic question

Choose an answer from memory. Your result tells you what to watch for in the guide.

Which statement correctly summarises momentum, conservation and safety?

Core revision guide

Learn the model, then use it

Momentum, Conservation and Safety questions become manageable when the central model, evidence and exam method are kept together. Read the explanation, test the misconception and then apply the idea without looking back.

Track momentum in collisions

Momentum is mass × velocity and is conserved in a closed system. Safety features reduce force by increasing collision time or reducing the change in momentum experienced by a person.

Build the physics picture

Momentum has direction, so choose a positive direction before adding values in a collision. In a closed system, total momentum before equals total momentum after. Airbags, seatbelts and crumple zones increase stopping time, reducing the average force for the same momentum change.

Relationships used in this guide

Momentum: p = mv (kg m/s, kg, m/s). Force and momentum change: F = Δp ÷ t (N, kg m/s, s). Choose each relationship from the physical change described, convert quantities into compatible units and keep the unit beside the final answer.

A collision diagram uses signed velocities and force-time curves show equal impulse with different stopping times and peak forces.
For the same momentum change, increasing stopping time reduces the average and peak force.Open the full-size exam diagram
Momentump = mvkg m/s, kg, m/s
Force and momentum changeF = Δp ÷ tN, kg m/s, s

Misconception clinic

Replace the tempting answer

Read each belief, say what is wrong with it, then compare your correction.

Tempting idea: Forgetting direction/signs.

Use instead: Momentum is mass × velocity and is conserved in a closed system. Safety features reduce force by increasing collision time or reducing the change in momentum experienced by a person.

Tempting idea: Using total mass before a collision incorrectly.

Use instead: Momentum has direction, so choose a positive direction before adding values in a collision. In a closed system, total momentum before equals total momentum after. Airbags, seatbelts and crumple zones increase stopping time, reducing the average force for the same momentum change.

Tempting idea: Saying airbags reduce momentum change to zero.

Use instead: Choose a positive direction, write total momentum before and after, then explain the safety mechanism using time and force.

Retrieval practice

Quick checks

1. Which exam method is most reliable for momentum, conservation and safety?

2. Which statement correctly applies momentum, conservation and safety to a question?

3. A pupil writes: “Forgetting direction/signs.” Which replacement is accurate?

Explore the relationship

Momentum and safety model

Change momentum or collision time, then calculate average force using F = Δp ÷ Δt.

What to notice: use the readout to describe how one variable changes when the other is controlled.

Worked examples

See the method being built

These examples expose the difference between a secure track momentum in collisions method and the common error “Forgetting direction/signs.”.

Example 1 · Calculate momentum

A 1200 kg car travels at 15 m/s. Find momentum.

  1. Use p = mv.
  2. Multiply 1200 × 15.
  3. Give kg m/s.
Show the answer

p = 18 000 kg m/s.

Example 2 · Collision conservation

A 2.0 kg trolley at 3.0 m/s hits a stationary 1.0 kg trolley and sticks. Find final velocity.

  1. Initial p = 2.0 × 3.0 = 6.0.
  2. Combined mass = 3.0 kg.
  3. v = 6.0 ÷ 3.0.
Show the answer

Final velocity = 2.0 m/s in the original direction.

Example 3 · Safety explanation

Explain how an airbag reduces injury.

  1. Identify same momentum change.
  2. State collision time increases.
  3. Link to average force.
Show the answer

The airbag increases stopping time, so the same change in momentum happens with a smaller average force.

Exam precision

Exam technique: Track momentum in collisions

Do this: Choose a positive direction, write total momentum before and after, then explain the safety mechanism using time and force.

Independent practice

Exam-style questions

Write an answer before opening the marking guidance. Then edit the exact phrase or step that would gain the next mark.

1. State the unit of momentum.

[1 mark]
Show marking guidance and model answer

Marking guidance: Award one mark for the precise statement shown in the model answer.

Model answer: kg m/s.

2. Calculate momentum of a 0.50 kg ball at 8.0 m/s.

[3 marks]
Show marking guidance and model answer

Marking guidance: Award one mark for the correct relationship, one for a valid substitution and one for the final answer with its unit.

Model answer: p = 0.50 × 8.0 = 4.0 kg m/s.

3. State the conservation rule for a closed system.

[1 mark]
Show marking guidance and model answer

Marking guidance: Award one mark for the precise statement shown in the model answer.

Model answer: Total momentum before equals total momentum after.

4. Explain why a crumple zone reduces force.

[3 marks]
Show marking guidance and model answer

Marking guidance: Award up to 3 marks for distinct physics points joined into a clear cause-and-effect chain.

Model answer: It increases collision time for the same change in momentum.

5. A 5 kg object has momentum 20 kg m/s. Find velocity.

[3 marks]
Show marking guidance and model answer

Marking guidance: Award one mark for the correct relationship, one for a valid substitution and one for the final answer with its unit.

Model answer: v = p/m = 20 ÷ 5 = 4.0 m/s.

6. Why is direction needed in a collision calculation?

[2 marks]
Show marking guidance and model answer

Marking guidance: 2 marks are available for relevant, linked physics points that match the model answer.

Model answer: Momentum is a vector, so opposite directions have opposite signs.

Questions pupils ask

Momentum, Conservation and Safety FAQs

What is the main idea in Momentum, Conservation and Safety?

Momentum is mass × velocity and is conserved in a closed system. Safety features reduce force by increasing collision time or reducing the change in momentum experienced by a person.

What mistake should I avoid in Momentum, Conservation and Safety?

Forgetting direction/signs. Momentum has direction, so choose a positive direction before adding values in a collision. In a closed system, total momentum before equals total momentum after. Airbags, seatbelts and crumple zones increase stopping time, reducing the average force for the same momentum change.

Useful next steps

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