GCSE Physics resources

AQA GCSE Electricity

Series and Parallel Circuits

Use conservation of charge at junctions and the idea of shared potential difference. In series current is constant; in parallel the branches have the same potential difference and the total current is the sum of branch currents.

AQA 8463AQA 8464 GCSE PhysicsCombined Science: Trilogy FoundationHigher

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The revision snapshot

Use conservation of charge at junctions and the idea of shared potential difference. In series current is constant; in parallel the branches have the same potential difference and the total current is the sum of branch currents.

By the end, you should be able to:

  • Explain circuit rules that always help.
  • Apply the electricity model, evidence or method to an unfamiliar exam context.
  • Recognise and correct this wrong turn: Mixing up the series and parallel rules.

Before you revise

Diagnostic question

Choose an answer from memory. Your result tells you what to watch for in the guide.

In a series circuit, current is…

Core revision guide

Learn the model, then use it

Series and Parallel Circuits questions become manageable when the central model, evidence and exam method are kept together. Read the explanation, test the misconception and then apply the idea without looking back.

Circuit rules that always help

Use conservation of charge at junctions and the idea of shared potential difference. In series current is constant; in parallel the branches have the same potential difference and the total current is the sum of branch currents.

Build the physics picture

At a junction, charge cannot build up, so the current entering equals the current leaving. In one series loop every coulomb passes every component. In parallel, each branch has the same potential difference as the supply while the current divides between branches.

The relationship for this guide

Resistance: V = IR (V, A, Ω). Choose each relationship from the physical change described, convert quantities into compatible units and keep the unit beside the final answer.

Standard-symbol series and parallel circuits show equal series current and current splitting at a parallel junction.
In series the current is the same throughout; in parallel each branch has the supply potential difference and branch currents add.Open the full-size exam diagram
ResistanceV = IRV, A, Ω

Misconception clinic

Replace the tempting answer

Read each belief, say what is wrong with it, then compare your correction.

Tempting idea: Mixing up the series and parallel rules.

Use instead: Use conservation of charge at junctions and the idea of shared potential difference. In series current is constant; in parallel the branches have the same potential difference and the total current is the sum of branch currents.

Tempting idea: Adding potential differences across parallel branches.

Use instead: At a junction, charge cannot build up, so the current entering equals the current leaving. In one series loop every coulomb passes every component. In parallel, each branch has the same potential difference as the supply while the current divides between branches.

Tempting idea: Forgetting the total current is the sum of branch currents.

Use instead: Mark the supply, junctions and component positions first, then apply one circuit rule at a time.

Retrieval practice

Quick checks

1. Across parallel branches, potential difference is…

2. At a junction, current entering is…

3. Two cells in series provide…

4. If one lamp fails in a simple series circuit…

5. Why are house circuits parallel?

Worked examples

See the method being built

These examples expose the difference between a secure circuit rules that always help method and the common error “Mixing up the series and parallel rules.”.

Example 1 · Series p.d.

Two series lamps have potential differences 2.0 V and 4.0 V. Find the supply p.d.

  1. Use the series rule.
  2. Add the potential differences.
  3. State volts.
Show the answer

Supply p.d. = 6.0 V.

Example 2 · Parallel current

A 1.2 A current reaches a junction. One branch carries 0.50 A. Find the other branch current.

  1. Use conservation of charge.
  2. Subtract branch current from total.
  3. State amperes.
Show the answer

Other branch current = 1.2 − 0.50 = 0.70 A.

Example 3 · Choose circuit type

A student wants two lamps that work independently. Choose a circuit and explain.

  1. Identify the required behaviour.
  2. Choose series or parallel.
  3. Use a circuit rule as the reason.
Show the answer

Use parallel. Each lamp has the supply potential difference and one branch can remain complete if the other lamp is removed.

Exam precision

Exam technique: Circuit rules that always help

Do this: Mark the supply, junctions and component positions first, then apply one circuit rule at a time.

Independent practice

Exam-style questions

Write an answer before opening the marking guidance. Then edit the exact phrase or step that would gain the next mark.

1. State what is the same everywhere in a series circuit.

[1 mark]
Show marking guidance and model answer

Marking guidance: Award one mark for the precise statement shown in the model answer.

Model answer: Current.

2. A 12 V supply is shared by two series resistors. One has 5 V. Find the other p.d.

[3 marks]
Show marking guidance and model answer

Marking guidance: Award one mark for the correct relationship, one for a valid substitution and one for the final answer with its unit.

Model answer: 12 − 5 = 7 V.

3. The currents in two parallel branches are 0.30 A and 0.45 A. Calculate total current.

[3 marks]
Show marking guidance and model answer

Marking guidance: Award one mark for the correct relationship, one for a valid substitution and one for the final answer with its unit.

Model answer: 0.30 + 0.45 = 0.75 A.

4. Explain why a voltmeter is connected across a parallel branch.

[3 marks]
Show marking guidance and model answer

Marking guidance: Award up to 3 marks for distinct physics points joined into a clear cause-and-effect chain.

Model answer: It measures the energy transferred per coulomb between the two points at either end of that branch.

5. Describe what happens to a series circuit when one component is removed.

[2 marks]
Show marking guidance and model answer

Marking guidance: 2 marks are available for relevant, linked physics points that match the model answer.

Model answer: The loop is broken, so current stops everywhere.

6. Explain why potential difference is not “used up” in a parallel circuit.

[3 marks]
Show marking guidance and model answer

Marking guidance: Award up to 3 marks for distinct physics points joined into a clear cause-and-effect chain.

Model answer: Each branch is connected across the supply, so each has the same energy transfer per coulomb as the supply.

Questions pupils ask

Series and Parallel Circuits FAQs

What is the main idea in Series and Parallel Circuits?

Use conservation of charge at junctions and the idea of shared potential difference. In series current is constant; in parallel the branches have the same potential difference and the total current is the sum of branch currents.

What mistake should I avoid in Series and Parallel Circuits?

Mixing up the series and parallel rules. At a junction, charge cannot build up, so the current entering equals the current leaving. In one series loop every coulomb passes every component. In parallel, each branch has the same potential difference as the supply while the current divides between branches.

Useful next steps

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