GCSE Physics resources

AQA GCSE Electricity

I-V Characteristics Required Practical

A characteristic needs enough measured operating points to reveal its shape. Measuring one resistance does not establish proportionality.

AQA 8463AQA 8464 GCSE PhysicsCombined Science: Trilogy FoundationHigher

Start here

The revision snapshot

A characteristic needs enough measured operating points to reveal its shape. Measuring one resistance does not establish proportionality.

By the end, you should be able to:

  • Collect signed I–V data safely.
  • Plot I against V with suitable axes.
  • Explain resistor, lamp and diode curve shapes.

Before you revise

Diagnostic question

Choose an answer from memory. Your result tells you what to watch for in the guide.

A resistor has (V,I) pairs (2,0.20), (4,0.40), (6,0.60). What supports Ohmic behaviour?

Read the feedback for every option
  1. V/I is 10 Ω at each point.
  2. This is proportionality under the measured conditions.
  3. Every non-zero I has a V/I ratio.
  4. Current rises with voltage.

Core revision guide

Learn the model, then use it

A characteristic needs enough measured operating points to reveal its shape. Measuring one resistance does not establish proportionality.

Measure both polarities safely

Scope: 8463 and 8464 · Foundation and Higher

Use a low-voltage supply, switch, variable resistor and test component with ammeter in series and voltmeter across it. Include an appropriate limiting resistor when testing a diode. Start with high resistance, vary the supply/current gradually and record paired V and I. Reverse the supply connections with power off to obtain negative V and I; stay within ratings.

Plot I against V

Scope: 8463 and 8464 · Foundation and Higher

Label V horizontally and I vertically and show both signs. A resistor at near-constant temperature gives a straight line through the origin. A lamp is increasingly less steep as its hot filament resistance rises. A diode shows little reverse current and substantial forward current after its conducting region is reached; do not claim an exactly universal threshold voltage.

Temperature control depends on the component

Scope: 8463 and 8464 · Foundation and Higher

Limit heating for the fixed resistor so its curve measures the intended constant-temperature behaviour. Heating is part of the filament lamp’s normal characteristic: record stable readings at each point. Repeat readings to check scatter and use suitable meter ranges without exceeding the component’s safe power.

A variable-resistor circuit measures current through a test component and potential difference across it, with polarity reversal shown.
Vary the current safely, record paired V and I readings, then reverse the supply to obtain negative readings when required.Open the full-size exam diagram
Resistance at a pointR = V ÷ IΩ, V, A

Misconception clinic

Replace the tempting answer

Read each belief, say what is wrong with it, then compare your correction.

Tempting idea: R increases with voltage.

Use instead: V/I is 10 Ω at each point. This is proportionality under the measured conditions.

Tempting idea: To force equal reverse and forward currents.

Use instead: Directionality remains. A diode’s forward current can rise sharply.

Retrieval practice

Quick checks

1. Why is a limiting resistor used in a diode test?

Read the feedback for every option
  1. Directionality remains.
  2. A diode’s forward current can rise sharply.
  3. The resistor does not change the diode’s intrinsic characteristic.
  4. The voltmeter still spans the diode.

Worked examples

See the method being built

Apply measure both polarities safely in the worked reasoning, then try the changed-context questions below.

Example 1 · Full I–V method

Scope: 8463 and 8464 · Foundation and Higher

Describe how to collect an I–V characteristic for a fixed resistor.

  1. Use a variable d.c. supply, ammeter in series and voltmeter in parallel.
  2. Take paired V and I readings in small steps.
  3. Reverse the supply and repeat for negative p.d.
Show the answer

Plot current against potential difference. The fixed resistor should give a straight line through the origin if its temperature is constant.

Example 2 · Identify a graph

Scope: 8463 and 8464 · Foundation and Higher

An I–V graph has almost no current for negative p.d. and then rises sharply for positive p.d. Identify the component.

  1. Look for one-way conduction.
  2. Compare with resistor and lamp behaviour.
  3. Name the component.
Show the answer

It is a diode, which conducts mainly in its forward direction.

Example 3 · Explain lamp curve

Scope: 8463 and 8464 · Foundation and Higher

Explain why the gradient of a filament lamp I–V graph falls at high p.d.

  1. High p.d. gives higher current.
  2. The filament temperature rises.
  3. Resistance rises, so current increases less per volt.
Show the answer

The lamp gets hotter and its resistance increases, producing a curve rather than a straight line.

Exam precision

Use the physics precisely

Do this: Describe polarity reversal with the supply off, component protection and stable paired readings. Link each curve shape to its component behaviour.

Independent practice

Exam-style questions

Write an answer before opening the marking guidance. Then edit the exact phrase or step that would gain the next mark.

1. Describe how to obtain the positive and negative portions of a component’s I–V graph.

[4 marks]

Scope: 8463 and 8464 · Foundation and Higher

Show marking guidance and model answer

Original PhysicsUK mark scheme: Point 1 (1 mark): Ammeter in series and voltmeter in parallel across component. Point 2 (1 mark): Vary the supply/variable resistance and record multiple stable V,I pairs. Point 3 (1 mark): Switch off, reverse supply polarity and collect negative readings within ratings. Point 4 (1 mark): Plot I on y against V on x with units and a suitable smooth trend. Award each distinct point once. Accept equivalent scientifically correct wording. No half marks.

  1. Ammeter in series and voltmeter in parallel across component. (1 mark)
  2. Vary the supply/variable resistance and record multiple stable V,I pairs. (1 mark)
  3. Switch off, reverse supply polarity and collect negative readings within ratings. (1 mark)
  4. Plot I on y against V on x with units and a suitable smooth trend. (1 mark)

Model answer: Measure current through the component and voltage across it at several settings. With the supply off reverse polarity, then collect negative readings safely. Plot I against V with signed axes.

2. Explain why a fixed resistor and a filament lamp can have different I–V graph shapes.

[3 marks]

Scope: 8463 and 8464 · Foundation and Higher

Show marking guidance and model answer

Original PhysicsUK mark scheme: Point 1 (1 mark): An Ohmic resistor held at constant temperature has nearly constant R and I proportional to V. Point 2 (1 mark): The lamp filament heats as current increases. Point 3 (1 mark): Higher temperature raises the filament resistance, so I rises less per additional volt. Award each distinct point once. Accept equivalent scientifically correct wording. No half marks.

  1. An Ohmic resistor held at constant temperature has nearly constant R and I proportional to V. (1 mark)
  2. The lamp filament heats as current increases. (1 mark)
  3. Higher temperature raises the filament resistance, so I rises less per additional volt. (1 mark)

Model answer: The resistor’s nearly constant resistance gives a straight line. The lamp warms, increasing its resistance, and therefore has a curve that becomes less steep.

Questions pupils ask

I-V Characteristics Required Practical FAQs

Why should a resistance wire cool between readings?

Temperature affects resistance, so cooling prevents temperature change from being mistaken for the effect of length.

Useful next steps

Connect this guide to your next task