GCSE Physics resources

AQA GCSE Electricity

Current, Charge and Potential Difference

A circuit transfers energy while charge circulates. Track how much charge passes each second separately from how much energy each coulomb transfers.

AQA 8463AQA 8464 GCSE PhysicsCombined Science: Trilogy FoundationHigher

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The revision snapshot

A circuit transfers energy while charge circulates. Track how much charge passes each second separately from how much energy each coulomb transfers.

By the end, you should be able to:

  • Define current and potential difference.
  • Calculate charge and transferred energy.
  • Choose correct meter connections.

Before you revise

Diagnostic question

Choose an answer from memory. Your result tells you what to watch for in the guide.

A lamp transfers 36 J when 6 C passes through it. What is its potential difference?

Read the feedback for every option
  1. This multiplies rather than divides.
  2. This reverses E/Q.
  3. 36/6 = 6 J/C = 6 V.
  4. Subtraction does not define potential difference.

Core revision guide

Learn the model, then use it

A circuit transfers energy while charge circulates. Track how much charge passes each second separately from how much energy each coulomb transfers.

Current and charge

Scope: 8463 and 8464 · Foundation and Higher

Current I is Q/t, measured in amperes: 1 A = 1 C/s. In metallic wires electrons move; conventional current is drawn from positive to negative around the external circuit. A complete path is needed for a steady current. Put the ammeter in series so the component’s charge flow passes through it.

Potential difference

Scope: 8463 and 8464 · Foundation and Higher

V = E/Q, measured in volts: 1 V = 1 J/C. A 6 V battery transfers 6 J per coulomb, rather than supplying 6 coulombs. A voltmeter spans the two terminals of the component and is connected in parallel. Charge does not disappear in a lamp; each passing coulomb transfers some energy to the lamp and surroundings.

Connect the models

Scope: 8463 and 8464 · Foundation and Higher

If 0.50 A flows for 20 s, Q = 10 C. Across 6.0 V, E = QV = 60 J. The same current can occur at different potential differences because resistance differs. A cell provides a direct potential difference; an alternating supply reverses its polarity periodically.

A standard circuit places an ammeter in series and a voltmeter in parallel across a component.
Current is measured through the component; potential difference is the energy transferred per coulomb across it.Open the full-size exam diagram
Charge flowQ = ItC, A, s
Potential differenceV = E ÷ QV, J, C

Misconception clinic

Replace the tempting answer

Read each belief, say what is wrong with it, then compare your correction.

Tempting idea: 216 V.

Use instead: This multiplies rather than divides. 36/6 = 6 J/C = 6 V.

Tempting idea: I = 4 A; V = 2 V.

Use instead: The definitions have been swapped. Current is C/s, voltage is J/C.

Retrieval practice

Quick checks

1. A lamp receives 2 C each second and transfers 4 J per coulomb. Which pair is correct?

Read the feedback for every option
  1. The definitions have been swapped.
  2. Current is C/s, voltage is J/C.
  3. 8 W is the power, not either quantity.
  4. Neither rate should be inverted.

Worked examples

See the method being built

Apply current and charge in the worked reasoning, then try the changed-context questions below.

Example 1 · Current from charge

Scope: 8463 and 8464 · Foundation and Higher

120 C passes a point in 60 s. Calculate current.

  1. Use I = Q ÷ t.
  2. Substitute 120 ÷ 60.
  3. Give amperes.
Show the answer

I = 2.0 A.

Example 2 · Charge moved

Scope: 8463 and 8464 · Foundation and Higher

A current of 0.40 A flows for 3.0 min. Calculate charge.

  1. Convert time to 180 s.
  2. Use Q = It.
  3. Substitute 0.40 × 180.
Show the answer

Q = 72 C.

Example 3 · Energy per charge

Scope: 8463 and 8464 · Foundation and Higher

A 12 V supply transfers energy to 5.0 C of charge. Calculate the energy.

  1. Use E = VQ.
  2. Substitute 12 × 5.0.
  3. Give joules.
Show the answer

E = 60 J.

Exam precision

Use the physics precisely

Do this: Convert current and time units before Q = It. Identify the component across which p.d. is measured before using E = QV.

Independent practice

Exam-style questions

Write an answer before opening the marking guidance. Then edit the exact phrase or step that would gain the next mark.

1. A current of 0.40 A flows for 75 s. Calculate the charge passing a point.

[3 marks]

Scope: 8463 and 8464 · Foundation and Higher

Show marking guidance and model answer

Original PhysicsUK mark scheme: Point 1 (1 mark): Q = It. Point 2 (1 mark): Q = 0.40 × 75. Point 3 (1 mark): Q = 30 C. Award each distinct point once. Accept equivalent scientifically correct wording. No half marks.

  1. Q = It. (1 mark)
  2. Q = 0.40 × 75. (1 mark)
  3. Q = 30 C. (1 mark)

Model answer: Q = It. Q = 0.40 × 75. Q = 30 C.

Acceptable answers: Expected result: Q = 30 C. Accept the unrounded value or a correctly rounded equivalent to two or more significant figures; accept equivalent units if converted correctly. No additional measurement interval is implied.

Marking notes: Method marks remain available after an arithmetic error. Carry an earlier numerical error into a later valid step; award that method point if the unit conversion and physics are correct. A fully correct answer with unit earns all marks unless working is expressly requested.

2. 60 C passes through a component across 12 V. Calculate the energy transferred.

[3 marks]

Scope: 8463 and 8464 · Foundation and Higher

Show marking guidance and model answer

Original PhysicsUK mark scheme: Point 1 (1 mark): E = QV. Point 2 (1 mark): E = 60 × 12. Point 3 (1 mark): E = 720 J. Award each distinct point once. Accept equivalent scientifically correct wording. No half marks.

  1. E = QV. (1 mark)
  2. E = 60 × 12. (1 mark)
  3. E = 720 J. (1 mark)

Model answer: E = QV. E = 60 × 12. E = 720 J.

Acceptable answers: Expected result: E = 720 J. Accept the unrounded value or a correctly rounded equivalent to two or more significant figures; accept equivalent units if converted correctly. No additional measurement interval is implied.

Marking notes: Method marks remain available after an arithmetic error. Carry an earlier numerical error into a later valid step; award that method point if the unit conversion and physics are correct. A fully correct answer with unit earns all marks unless working is expressly requested.

Questions pupils ask

Current, Charge and Potential Difference FAQs

Does a lamp use up current?

No. In a steady series circuit the same charge per second passes each point. The lamp transfers energy carried by the charge.

Useful next steps

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