Simple Harmonic Motion, Damping and Resonance | AQA A-level Physics

AQA 7408 · Section 3.6.1 · A-level only

Simple harmonic motion, damping and resonance

Connect the defining equation to motion graphs, energy, oscillators and resonance. Make a prediction, test it in the SHM Explorer, then answer the exam questions without relying on pattern matching.

19 specification pointsRequired Practical 7Interactive SHM Explorer
Exam-style diagram of a mass-spring oscillator, displacement velocity and acceleration graphs, and resonance curves with different damping

Predict, test, explain

1

Predict

State the sign, direction or graph shape before touching a control.

2

Test

Change one quantity in the model and compare the result with your prediction.

3

Explain

Use a defining equation and physical reasoning, then attempt the exam question.

What makes motion simple harmonic?

Simple harmonic motion is oscillation in which acceleration is proportional to displacement from equilibrium and always directed back towards equilibrium.

a ∝ −x
a = −ω²x

The minus sign describes direction. At positive displacement, acceleration is negative; at negative displacement, acceleration is positive. At equilibrium, acceleration is zero but speed is greatest.

Examiner-report trap“Acceleration is proportional to displacement” is incomplete. A full SHM condition needs the restoring direction: acceleration is proportional to negative displacement.
x = A cos(ωt)
v = ±ω√(A² − x²)
vmax = ωA
amax = ω²A

The ± sign in the velocity equation matters because the oscillator can pass the same displacement in either direction. Speed is a magnitude; velocity has a direction.

PositionVelocityAccelerationEnergy
x = +A0−ω²AMaximum potential; zero kinetic
x = 0Maximum magnitude0Maximum kinetic; minimum potential
x = −A0+ω²AMaximum potential; zero kinetic

Phase and sign checkpoint

A mass is at x = +0.60A and moving towards equilibrium. Select the only correct statement.

Commit to an answer before checking.

Use the PhysicsUK SHM Explorer

Change amplitude, frequency and phase. Pause at an instant and compare the oscillator with the x–t, v–t and a–t graphs. The gradient of an x–t graph is velocity; the gradient of a v–t graph is acceleration.

Three challengesFind an instant when x is positive but v is negative. Find where |v| is maximum. Then double frequency and explain why maximum acceleration changes by a factor of four.

Springs, pendulums and energy transfer

Mass–spring system

T = 2π√(m/k)

Increasing mass increases the period. Increasing spring constant makes the system stiffer and decreases the period. The period does not depend on amplitude while the system remains within the SHM model.

Simple pendulum

T = 2π√(l/g)

This relation is approximate because the derivation uses the small-angle approximation. Measure length from the pivot to the centre of the bob, not to its top or bottom.

Energy in ideal SHM

Etotal = ½mω²A²
Ek = ½mω²(A² − x²)
Ep = ½mω²x²

With no damping, kinetic and potential energy exchange while total energy stays constant. Energy graphs against displacement are parabolic. Against time, kinetic and potential energy repeat twice in every oscillation.

Graph reasoningA flat displacement graph means zero velocity at that instant, not zero acceleration. Use gradients rather than judging the height of the curve.

Damping, forced vibrations and resonance

Free vibration

After one displacement, the system oscillates at its natural frequency. Damping removes energy and reduces amplitude.

Forced vibration

A periodic driving force makes the system vibrate at the driving frequency after transients have faded.

Resonance

Amplitude is greatest when driving frequency is close to natural frequency because energy transfer is most effective.

Common misconceptionDamping does more than lower the resonance peak. Greater damping also broadens the response, so resonance is less sharp. Avoid claiming that damping simply “stops resonance”.

Resonance curve investigation

Predict how the peak changes, then adjust damping. The curve is qualitative and intended for comparison.

Investigate SHM with a spring and a pendulum

Mass–spring method

  1. Clamp the spring securely and measure the mass, including the mass hanger.
  2. Displace the mass vertically by a small amount and release without pushing.
  3. Time at least 10 complete oscillations, repeat, average, then divide by the number of cycles.
  4. Change mass while keeping the same spring and a small amplitude.
  5. Plot T² against m. From T² = (4π²/k)m, gradient = 4π²/k.

Pendulum method

  1. Measure l from the pivot to the centre of the bob.
  2. Use a small angle and release without a push.
  3. Time repeated oscillations as the bob passes a fiducial marker in the same direction.
  4. Repeat for a range of lengths.
  5. Plot T² against l. From T² = (4π²/g)l, gradient = 4π²/g.
Uncertainty and evaluationTiming many cycles reduces percentage reaction-time uncertainty. Repeat timings, use a wide range of the independent variable, avoid parallax in length measurements and use the best-fit gradient. A non-zero intercept can indicate a systematic length or mass offset.

Required Practical graph analysis

Use the gradient of a T² graph to recover k or g. Enter a best-fit gradient, not two neighbouring data points.

Choose the graph and enter its gradient.

Questions and worked answers

1. An oscillator has amplitude 0.080 m and frequency 1.5 Hz. Calculate its maximum speed and maximum acceleration. [4 marks]

ω = 2πf = 9.42 rad s⁻¹. vmax = ωA = 0.754 m s⁻¹. amax = ω²A = 7.11 m s⁻².

2. A particle is at x = 0.030 m in SHM with ω = 8.0 rad s⁻¹. State the acceleration and explain its sign. [3 marks]

a = −ω²x = −8.0² × 0.030 = −1.92 m s⁻². The negative sign means acceleration is towards equilibrium from a positive displacement.

3. A 0.40 kg mass oscillates on a spring of constant 63 N m⁻¹. Find the period. [2 marks]

T = 2π√(m/k) = 2π√(0.40/63) = 0.50 s.

4. Explain the energy changes from maximum positive displacement to equilibrium. [3 marks]

Potential energy decreases while kinetic energy increases. Speed rises from zero to its maximum. In ideal SHM total mechanical energy remains constant.

5. Explain why the pendulum equation becomes less accurate at large amplitude. [2 marks]

The derivation assumes a small angle so sin θ ≈ θ when θ is measured in radians. At larger angles this approximation fails, so the restoring acceleration is not exactly proportional to displacement.

6. A T²–l graph has gradient 4.05 s² m⁻¹. Determine g. [3 marks]

Gradient = 4π²/g, so g = 4π²/4.05 = 9.75 m s⁻².

7. Describe how greater damping changes a resonance curve. [3 marks]

The maximum amplitude is lower, the peak is broader and resonance is less sharp. The frequency at maximum amplitude may also shift slightly lower for appreciable damping.

8. A bridge is driven periodically by wind. Explain one design approach that reduces dangerous resonance. [3 marks]

Add damping so energy is dissipated, lowering and broadening the resonance response, or change stiffness/mass to move the natural frequency away from likely driving frequencies. The explanation must link the design change to reduced oscillation amplitude.

AQA 7408 coverage

  • 3.6.1.2(a) Analyse the characteristics of simple harmonic motion.
  • 3.6.1.2(b) Use the condition for SHM that acceleration is proportional to negative displacement.
  • 3.6.1.2(c) Use the defining equation a = −ω²x.
  • 3.6.1.2(d) Use x = A cosωt for displacement in SHM.
  • 3.6.1.2(e) Use v = ±ω√(A² − x²) for speed in SHM.
  • 3.6.1.2(f) Link graphical variations of displacement, velocity and acceleration with time.
  • 3.6.1.2(g) Use gradients to connect x-t, v-t and a-t graphs for SHM.
  • 3.6.1.2(h) Use maximum speed = ωA.
  • 3.6.1.2(i) Use maximum acceleration = ω²A.
  • 3.6.1.3(a) Use T = 2π√(m/k) for a mass-spring system.
  • 3.6.1.3(b) Use T = 2π√(l/g) for a simple pendulum.
  • 3.6.1.3(c) Apply provided information to other harmonic oscillators where required.
  • 3.6.1.3(d) Describe variation of kinetic energy, potential energy and total energy with displacement and time in SHM.
  • 3.6.1.3(e) Describe effects of damping on oscillations.
  • 3.6.1.3(f) Recognise the small-angle approximation in derivations of time period for approximate SHM.
  • 3.6.1.4(a) Describe free vibrations and forced vibrations qualitatively.
  • 3.6.1.4(b) Explain resonance.
  • 3.6.1.4(c) Explain how damping affects the sharpness of resonance.
  • 3.6.1.4(d) Apply resonance and damping to mechanical systems and stationary-wave situations.
  • 8.2.RP7 Investigate simple harmonic motion using a mass-spring system and a simple pendulum.

Written against AQA Physics 7408 sections 3.6.1.2–3.6.1.4 and Required Practical 7. Questions are original and examiner-report misconceptions are paraphrased for teaching.

Written by: PhysicsUK teaching team

Expertise: Built by a UK A Level Physics teacher and examiner.

Reviewed for: AQA A Level Physics 7408

Last reviewed: 2026-07-15

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