AQA 7408 · Section 3.5.1

Current, charge and electrical energy

Connect charge flow to potential difference, energy and power. Predict the effect of each change, then use the live model to check your reasoning.

4 PhysicsUK checklist pointsInteractive energy modelOriginal exam questions
Current I is vertical and voltage V horizontal. An ohmic conductor is a straight line through the origin. The filament lamp has symmetric positive and negative branches and decreasing slope as the voltage magnitude rises. A diode has negligible reverse current and a steep forward branch. Curves are qualitative.
Current is vertical and p.d. horizontal. Heating raises a filament lamp’s resistance, so its I–V curve flattens in both directions. All curves are qualitative. Open full-size labelled diagram.

Predict, test, explain

1

Predict

Commit to a direction or value before moving a control.

2

Test

Change one variable and compare the evidence with your prediction.

3

Explain

Use an equation and a physical reason, then attempt the exam questions.

Follow the charge and the energy

Current

I = ΔQ / Δt

Current is the rate of flow of charge. A current of 1 A means 1 C passes a point each second. Charge is conserved: components transfer energy, not charge.

Potential difference

V = W / Q

Potential difference is the work done per unit charge. One volt is one joule per coulomb.

Energy and power

E = IVt
P = IV = I²R = V²/R

Power is the rate of energy transfer. Select the power equation that uses known quantities; do not treat the three forms as unrelated facts.

Common misconceptionCurrent is not “used up”. If current falls across an ordinary component in a steady series circuit, the model violates conservation of charge.

Electrical energy transfer laboratory

Predict before changing the controls

How will doubling voltage affect power if resistance stays constant? Test it, then explain using P = V²/R.

A reliable four-step method

1. Identify

Write the quantity required and its unit.

2. Convert

Convert minutes, mA and kΩ before substitution.

3. Select

Choose the equation containing the known quantities.

Units checkA × V = W, and W × s = J. A numerical answer without a unit is incomplete.

Questions and worked answers

1. A 0.40 A current flows for 3.0 minutes. Find the charge transferred. [2 marks]

t = 180 s. Q = It = 0.40 × 180 = 72 C.

2. A motor transfers 540 J when 45 C passes through it. Find the p.d. [2 marks]

V = W/Q = 540/45 = 12 V.

3. A 24 Ω heater is connected to 12 V for 5.0 minutes. Calculate the energy transferred. [4 marks]

P = V²/R = 144/24 = 6.0 W. E = Pt = 6.0 × 300 = 1.8 × 10³ J.

4. Explain why the current entering a lamp equals the current leaving it. [2 marks]

Charge is conserved and does not steadily accumulate inside the lamp. Therefore the rate of charge flow into it equals the rate out.

AQA 7408 coverage

Letter suffixes in this checklist are PhysicsUK subdivisions for navigation. The official AQA references are the numbered sections above.

  • 3.5.1.1(a) Define electric current as the rate of flow of charge, I = ΔQ/Δt.
  • 3.5.1.1(b) Define potential difference as work done per unit charge, V = W/Q.
  • 3.5.1.4(c) Use electrical energy equation E = IVt.
  • 3.5.1.4(d) Use power equations P = IV, P = I²R and P = V²/R.

Written against AQA Physics 7408 section 3.5.1. All questions are original and designed for active revision.

Written by: PhysicsUK teaching team

Expertise: Built by a UK A Level Physics teacher and examiner.

Reviewed for: AQA A Level Physics 7408

Last reviewed: 2026-10-07

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