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AS Daily A Level Physics question

2025-11-07 OCR A Kinematics (M3.1) — displacement–time graphs 3.1.1(a)

A delivery robot moves along a straight corridor. Its displacement–time graph is a straight line from 0 m at t = 0 s to +5 m at t = 10 s, then a straight line to −1 m at t = 20 s (it passes the origin and ends 1 m on the other side). Which value is the robot’s average speed over 0–20 s?

  1. A 0.05 m/s
  2. B 0.50 m/s
  3. C 0.30 m/s
  4. D 0.55 m/s (correct)

Answer

The correct answer is D.

Correct: D — 0.55 m/s. A uses net displacement over time (|−1 m|/20 s), which gives the magnitude of average velocity, not average speed. B takes only the first 10 s (5 m in 10 s) and ignores the return leg. C adds 5 m and 1 m, misreading the second segment; the robot actually travels 6 m from +5 m to −1 m. D uses total distance (5 m + 6 m = 11 m) over total time (20 s), so 11/20 = 0.55 m/s.