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AS Daily A Level Physics question

2025-10-26 OCR A Archimedes principle 3.2.4(a) 3.2.4(c)

A 2.0 kg wooden block of volume 4.0×10^−3 m^3 is held fully submerged in fresh water by a light vertical string attached to the tank floor. The string is cut and the block rises, then settles floating partially submerged. Which statement must be true?

  1. A The string’s tension was downward and about 20 N; once it floats freely, roughly 50% of the block’s volume is submerged. (correct)
  2. B The string’s tension was upward and about 20 N; once it floats freely, roughly 50% of the block’s volume is submerged.
  3. C The string carried no tension at rest because upthrust equals weight when fully submerged; once released the block remains fully submerged.
  4. D The string’s tension was downward and about 40 N; once it floats freely, nearly all of the block’s volume is submerged.

Answer

The correct answer is A.

Correct: A — The string’s tension was downward and about 20 N; once it floats freely, roughly 50% of the block’s volume is submerged. Fully submerged, the upthrust is ρwater g V ≈ 1000×9.81×0.004 ≈ 39 N, while the weight is mg ≈ 19.6 N, so the string must pull downward with about 39−19.6 ≈ 20 N to hold it; when floating, the submerged fraction equals the density ratio m/(ρwater V) = 2/(1000×0.004) = 0.50. B is wrong because the string must act downward (the fluid pushes up more than weight when fully submerged), not upward, even though the 50% fraction is correct. C is wrong because upthrust equals weight only at floating equilibrium, not when forced fully submerged here; the block will not remain fully submerged once released. D is wrong because 40 N confuses the upthrust with the required tension (which is the difference upthrust−weight), and a less-dense-than-water block cannot end up nearly fully submerged when floating.