Back to Daily Question archive

A2 Daily A Level Physics question

2025-11-04 OCR A Thermal physics I: internal energy; specific heat; energy changes; heating curves (qual.) 5.1.3(a) 5.1.3(c)

Two identical insulated beakers are each heated by the same 100 W immersion heater for 60 s, with stirring. Beaker X contains 0.10 kg of ice at −5°C. Beaker Y contains 0.10 kg of liquid water at +5°C. Which statement must be true immediately after the heating?

  1. A Both samples show the same temperature rise because they receive the same 6000 J.
  2. B Y warms by about 14°C, while X is held at 0°C with ice still present. (correct)
  3. C X ends hotter than Y because ice has a smaller specific heat so gains more temperature.
  4. D Both end near 0°C since 6000 J is too little to change temperature much.

Answer

The correct answer is B.

Correct: B — Y warms by about 14°C, while X is held at 0°C with ice still present. A ignores that temperature rise depends on specific heat and phase changes; same 6000 J gives different ΔT, and in X most energy is used without raising temperature beyond 0°C. B is correct because Y’s rise is ΔT ≈ 6000 J ÷ (0.10 kg × 4200 J kg⁻¹ K⁻¹) ≈ 14°C, whereas X uses 0.10×2100×5 ≈ 1050 J to reach 0°C and the remaining 4950 J goes into melting (latent heat), keeping it at 0°C. C reverses the outcome by focusing only on lower specific heat of ice and neglecting the large latent heat needed to melt it. D is wrong because 6000 J is sufficient to raise 0.10 kg of liquid water by over 10°C, not leave it “near 0°C.”