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Springs and Newton’s second law Forces explain changes in motion Motion3.1 Forces in action3.2 Dynamics3.2.1 Springs3.4.1
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Course idea

Dynamics

OCR A AS Physics · 3.2.1

Explore dynamics within forces in action. Start with the object and draw all forces acting on it. Their vector sum determines acceleration; zero resultant force gives constant velocity, including rest.

Specification outcomes (6)
  • 3.2.1(a) Apply Newton’s second law, F = ma.
  • 3.2.1(b) Define the newton as the unit of force.
  • 3.2.1(c) Understand weight of an object, W = mg.
  • 3.2.1(d) Define and identify tension, normal contact force, upthrust and friction.
  • 3.2.1(e) Draw and interpret free-body diagrams.
  • 3.2.1(f) Describe one- and two-dimensional motion under constant force.
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H156 v2.0 · May 2026

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PhysicsUK QWC6 marks

A technician compares two spring bumpers for a horizontal trolley. Spring A has a straight force-extension loading graph through the origin. Spring B has a curved loading graph but returns fully to its original length when unloaded. Both are used within a range where no permanent deformation occurs. Assume there are no internal energy losses within either spring on loading or unloading. A pupil makes two claims: “Elastic always means force is proportional to extension, so 0.5kx² gives the stored energy for both springs” and “The trolley accelerates at a constant rate until it leaves either spring.” Evaluate both claims. Explain how the force-extension graph gives the work done loading each spring, how this relates to energy transferred on release, and the effect of a constant resistive force on the trolley's motion. Assume the spring masses are negligible. [6]

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