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55 ideas · 9 connections
Springs and Newton’s second law Springs and equilibrium Spring force and elastic energy Springs and graph interpretation Materials3.4 Dynamics3.2.1 Equilibrium3.2.3 Springs3.4.1 Elastic potential energy Force–extension graphs
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Springs and Newton’s second law

OCR A AS Physics · Two ideas, one explanation

A spring force is one contribution to the resultant force on an object. Combine it with weight, friction or other forces before using Newton’s second law.

Fspring = kx ΣF = ma

Follow the reasoning

  1. Choose the object and draw its free-body diagram.
  2. Find the spring deformation from its natural length and calculate the force magnitude kx.
  3. Choose a positive direction and add all forces with signs.
  4. Divide the resultant force by the mass to find acceleration.
Specification outcomes (3)
  • 3.4.1(b) State and apply Hooke’s law.
  • 3.4.1(c) Define the force constant k of a spring or wire using F = kx.
  • 3.2.1(a) Apply Newton’s second law, F = ma.
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H156 v2.0 · May 2026

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PhysicsUK QWC6 marks

A technician compares two spring bumpers for a horizontal trolley. Spring A has a straight force-extension loading graph through the origin. Spring B has a curved loading graph but returns fully to its original length when unloaded. Both are used within a range where no permanent deformation occurs. Assume there are no internal energy losses within either spring on loading or unloading. A pupil makes two claims: “Elastic always means force is proportional to extension, so 0.5kx² gives the stored energy for both springs” and “The trolley accelerates at a constant rate until it leaves either spring.” Evaluate both claims. Explain how the force-extension graph gives the work done loading each spring, how this relates to energy transferred on release, and the effect of a constant resistive force on the trolley's motion. Assume the spring masses are negligible. [6]

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