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AS Daily A Level Physics question

2026-06-24 OCR A SUVAT problems (Module 3.1.1 Motion) OCR-A 3.1.1 Motion: uniform acceleration; equations of motion (suvat) OCR-A 3.1.1 Motion: velocity–time reasoning; stopping distance relationships

A car on a dry road brakes with a steady deceleration. From 15 m/s it takes 20 m to come to rest. Under the same conditions, what is the stopping distance from 30 m/s (ignore reaction time)?

  1. A 80 m (correct)
  2. B 40 m
  3. C 20 m
  4. D 60 m

Answer

The correct answer is A.

Correct: A — 80 m. With the same constant deceleration, stopping distance is proportional to the square of the initial speed, so doubling speed makes distance ×4: 4 × 20 m = 80 m. A … B — 40 m assumes distance is proportional to speed (doubling speed doubles distance), but the distance scales with speed squared, not linearly. C — 20 m implies stopping distance is independent of initial speed, which is false. D — 60 m reflects a mix-up between time and distance; while stopping time doubles when speed doubles, the distance increases by a factor of four, not three.