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AS Daily A Level Physics question

2026-06-16 OCR A DC Circuits (M4) 4.1.1 Charge and current 4.2.1 Energy, power and resistance 4.3.1 d.c. circuits

In a lab test, a bench power supply is set to 6.0 V and connected to a resistor using long, thin leads. The current is 0.50 A. A voltmeter across just the resistor reads 5.8 V. Which statement must be true about the energy transfer per coulomb in this circuit?

  1. A Each coulomb gains 5.8 J from the source, and 0.2 J is lost in the resistor.
  2. B Each coulomb gains 6.0 J from the source; 5.8 J is delivered to the resistor and 0.2 J is dissipated in the leads. (correct)
  3. C Each coulomb gains 5.8 J from the source; the extra 0.2 J appears as chemical energy in the supply.
  4. D Each coulomb gains 6.0 J from the source; all 6.0 J is delivered to the resistor, and the leads dissipate no energy because they are just wires.

Answer

The correct answer is B.

Correct: B — Each coulomb gains 6.0 J from the source; 5.8 J is delivered to the resistor and 0.2 J is dissipated in the leads. A confuses source e.m.f. with the terminal p.d. across the load: the supply provides 6.0 J per coulomb, not 5.8 J. B is correct because e.m.f. is the energy per coulomb supplied; the 0.2 V drop in the leads means 0.2 J per coulomb is dissipated there. C invents energy gain in the supply; the 0.2 J per coulomb is not stored but lost as heating in the leads indicated by their voltage drop. D ignores the measured 0.2 V across the leads; a non-zero p.d. across them means energy per coulomb is dissipated in the leads, not all in the resistor.