Back to Daily Question archive

AS Daily A Level Physics question

2026-06-07 OCR A Waves & Optics: Refraction and TIR (Module 4) Module 4.4.1 Refraction and refractive index (AS Physics A) Module 4.4.2 Total internal reflection; critical angle; optical fibres (qualitative)

A narrow laser beam travels inside a glass block (refractive index 1.50) and strikes the glass–air boundary from the glass side. As the angle of incidence inside the glass is slowly increased, at roughly what angle to the normal will total internal reflection just begin?

  1. A about 30° to the normal
  2. B about 48° to the normal
  3. C about 60° to the normal
  4. D about 42° to the normal (correct)

Answer

The correct answer is D.

Correct: D — about 42° to the normal. At the onset of total internal reflection from glass to air, sin(critical angle) ≈ n_air/n_glass = 1.00/1.50 ≈ 0.67, so the angle is arcsin(0.67) ≈ 42°. A is wrong because 30° would require sinθ ≈ 0.5, implying n_air/n_glass ≈ 0.5, which is too small for glass–air. B is wrong because ~48° is close to the water–air critical angle (n≈1.33), not glass. C is wrong because 60° (sin60° ≈ 0.87) would imply n_air/n_glass ≈ 0.87, inconsistent with glass being much denser optically than air.