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AS Daily A Level Physics question

2026-05-06 OCR A Mechanics & Materials (M3) OCR-A Module 3.1 — Forces and motion: Newton’s laws of motion (Newton’s third law; contact forces) OCR-A Module 3.1 — Free-body diagrams and interaction pairs

In a lab, two low-friction trolleys are coupled by a rigid bar. A student pulls the front trolley with a horizontal force so that both trolleys speed up together along a straight track. Considering only the horizontal interaction at the coupling, which statement must be true at every moment while they accelerate?

  1. A The force on the rear trolley from the front one is less than the force on the front trolley from the rear one, because the front trolley is being pulled by the student.
  2. B The force on the rear trolley from the front one is greater than the force on the front trolley from the rear one, because the pair accelerates forward.
  3. C The force on the rear trolley from the front one equals the force on the front trolley from the rear one in magnitude, acting in opposite directions, even while they speed up. (correct)
  4. D The two forces at the coupling become equal only after a short time, once the speed becomes steady; during acceleration the front-on-rear force is larger.

Answer

The correct answer is C.

Correct: C — The force on the rear trolley from the front one equals the force on the front trolley from the rear one in magnitude, acting in opposite directions, even while they speed up. A confuses the external pull with the interaction pair at the coupling; the third-law pair there must be equal and opposite. B assumes acceleration makes the forces unequal, but third-law pairs are equal at every instant and act on different bodies. C correctly states Newton’s third-law relationship and that it is independent of whether the motion is speeding up or steady. D wrongly links equality to constant speed, mixing up net force (second law) with action–reaction pairs (third law).