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A2 Daily A Level Physics question

2026-06-16 OCR A Energy & power in DC circuits OCR-A 4.1.2 Energy, power and resistance (energy and power in DC circuits)

A 3.0 V head torch originally uses a 0.60 W filament bulb. It is upgraded to a 1.2 W LED module, still powered by the same 3.0 V battery pack. For a continuous 30 min walk, which value is closest to the extra electrical energy taken from the battery by the LED compared with the original bulb?

  1. A 600 J
  2. B 0 J
  3. C 1080 J (correct)
  4. D 2160 J

Answer

The correct answer is C.

Correct: C — 1080 J. The LED uses an extra 0.60 W compared with the bulb; over 30 min = 1800 s this extra energy is 0.60 × 1800 = 1080 J. A is incorrect because 600 J underestimates the time or uses a rounded duration (about 10 min rather than 30 min). B is incorrect because at higher power the device takes more energy per second, so the extra over 30 min cannot be zero. C is correct as it uses the power difference multiplied by time. D is incorrect because 2160 J is the total energy used by the LED alone (1.2 W × 1800 s), not the extra above the original bulb.