A2 Daily A Level Physics question
In a lab, a mass–spring system is driven by a shaker providing a sinusoidal force of fixed amplitude. With light damping, the resonance peak occurs at f0 = 2.0 Hz, and the two half-power frequencies are measured as 1.8 Hz and 2.2 Hz. A second identical damping vane is then added so that the resistive (drag) coefficient doubles; the shaker force amplitude is unchanged. Which outcome is most consistent with this change?
Answer
The correct answer is C.
Correct: C — Peak amplitude halves; the half-power width Δf grows to about 0.8 Hz; the peak frequency is almost unchanged. Doubling the damping (energy dissipated per cycle) reduces the resonant amplitude roughly in inverse proportion, and broadens the resonance; the initial half-power width is 2.2−1.8 = 0.4 Hz, so doubling damping gives Δf ≈ 0.8 Hz, while the peak frequency shifts only slightly for light damping. A … Increased damping does not narrow the resonance; it broadens it, and the peak frequency does not rise noticeably (it tends to drop slightly, if at all). B … The amplitude does not increase when damping is increased; it decreases, though the doubling of Δf is correct and the peak frequency changes little. C … Matches the expected inverse effect on peak amplitude and proportional increase in bandwidth, with only a small change in peak frequency. D … Damping affects both amplitude and bandwidth; leaving them unchanged while claiming a large downward shift in peak frequency contradicts the behaviour of a lightly damped driven oscillator.