A2 Daily A Level Physics question
A clean photoemissive cathode is uniformly illuminated by a monochromatic beam from a tuneable LED. The optical power delivered to the cathode is the same in both cases, and the illuminated area is unchanged. Setting 1 uses frequency f_R. Setting 2 uses frequency f_V = 1.5 f_R. The metal’s threshold frequency is f_T = 1.2 f_R. A circuit can measure the photocurrent (with a small collecting field) and the stopping potential. Which statement must be true when switching from f_R to f_V?
Answer
The correct answer is A.
Correct: A — At f_R (< f_T) there is no emission; at f_V (> f_T) emission occurs. For equal power, the photon arrival rate at f_V is 2/3 of that at f_R, so the photocurrent at f_V is proportional to this lower rate; the stopping potential rises from 0 to a value set by 0.3 of the f_R photon energy per electron. A combines the threshold condition (below f_T no emission) with the inverse relation between photon rate and frequency at fixed power (2/3 here) and the increase in maximum electron energy (proportional to f_V − f_T = 0.3 f_R), giving a non-zero stopping potential. B assumes intensity alone controls emission and that higher-frequency photons create more electrons rather than more energetic ones; it also wrongly claims the stopping potential is independent of frequency. C incorrectly denies emission even when f_V exceeds f_T and falsely states that increasing frequency at fixed power does not change photon energy or stopping potential. D ties emission to photon rate rather than exceeding the threshold and links stopping potential to intensity; in fact f_V (> f_T) would produce emission and a larger stopping potential despite the lower photon rate.