A2 Daily A Level Physics question
In a vacuum photocell, a clean sodium cathode (work function 2.3 eV) is illuminated with monochromatic 300 nm light, giving a stopping potential about 1.8 V. The lamp is replaced with a 600 nm source of the same intensity. What is the new stopping potential? Support your answer with a short numerical estimate.
Answer
The correct answer is A.
Correct: A — 0 V, because the photon energy at 600 nm (~2.1 eV) is below the 2.3 eV work function so no electrons are emitted. A states there are no photoelectrons, so the stopping potential is zero; 1240/600 ≈ 2.07 eV < 2.3 eV confirms this. B wrongly assumes stopping potential scales directly with frequency from zero, ignoring the threshold; below threshold there is no emission, not a halved value. C confuses intensity with photon energy; intensity affects photocurrent, not the maximum kinetic energy or stopping potential. D misunderstands sign and collection; with no photoelectrons there is no current to stop, so no finite or negative stopping potential applies.