A2 Daily A Level Physics question
An ultrasound A-scan sends the same normal-incidence pulse through soft tissue (acoustic impedance 1.6 MRayl) toward two planar boundaries in a phantom: (i) soft tissue to bone (7.0 MRayl) and (ii) soft tissue to muscle (1.7 MRayl). Ignore absorption between the transducer and the boundary. Which statement about the reflected intensity fractions is most consistent with these values?
Answer
The correct answer is A.
Correct: A — Roughly 40% is reflected at the soft tissue–bone boundary but less than 0.1% at the soft tissue–muscle boundary, so the bone echo is hundreds of times stronger. A Using the amplitude ratio at normal incidence (difference over sum of impedances) gives r ≈ (7.0−1.6)/(7.0+1.6) ≈ 0.63 for bone, so intensity reflection ≈ 0.63^2 ≈ 0.40; for muscle r ≈ (1.7−1.6)/(1.7+1.6) ≈ 0.03, so intensity reflection ≈ 0.0009 ≈ 0.09%. B Treats the amplitude ratio as the intensity fraction and so overestimates both reflections (63% and 3% are amplitudes, not intensities). C Reflection at normal incidence depends primarily on impedance mismatch, not on the shared frequency; the near-matched tissue–muscle interface reflects very little. D Coupling gel reduces reflection at the skin by removing the air gap and improving matching; it does not increase reflections from deeper internal boundaries.