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A2 Daily A Level Physics question

2026-02-15 OCR A Consolidation: mechanics & materials mixed reasoning Module 3.4 Materials: Young modulus; load–extension relationships Module 1 Practical skills: Determination of Young modulus of a metal wire; gradients and proportional reasoning

In a Young modulus practical, a student measures the gradient of a load–extension graph for a metal wire of length L and diameter d (small elastic extensions). They then replace it with a wire of the same material but length 2L and diameter 0.5d, using the same load range. Which statement about the new graph's gradient is correct, and why?

  1. A It decreases by a factor of 8, because extension for a given load scales with length and inversely with cross-sectional area (area ∝ d^2). (correct)
  2. B It increases by a factor of 8, because halving the diameter makes the wire four times stiffer and doubling the length doubles the stiffness.
  3. C It decreases by a factor of 4, because halving the diameter only halves the area, and length does not affect the gradient.
  4. D It increases by a factor of 4, because the longer wire behaves like more of the same material in parallel, giving a steeper load–extension graph.

Answer

The correct answer is A.

Correct: A — It decreases by a factor of 8, because extension for a given load scales with length and inversely with cross-sectional area (area ∝ d^2). A is consistent with extension per unit force increasing eightfold (2 from length and 4 from area), so the gradient (force per extension) must reduce by 8. B reverses the inference: reducing area and increasing length both reduce stiffness, so the gradient cannot increase. C underestimates the effect by treating area as proportional to diameter (not diameter squared) and also ignores the doubling of length. D confuses series/parallel reasoning: making a wire longer is like adding springs in series (less stiff), and halving the diameter further reduces stiffness, so the gradient would not be steeper.