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A2 Daily A Level Physics question

2026-02-05 OCR A Kinematics: equations of motion (suvat) OCR A H556 Module 3: Forces and motion — 3.1.2 Motion (constant acceleration, equations of motion)

A car passes point X at 20 m/s and, 100 m further on at point Y, it is moving at 15 m/s, having braked uniformly between X and Y. If the driver continues to brake at the same rate after Y, approximately how much further will the car travel before coming to rest?

  1. A about 75 m
  2. B about 100 m
  3. C about 300 m
  4. D about 130 m (correct)

Answer

The correct answer is D.

Correct: D — about 130 m. A assumes stopping distance is proportional to speed (taking 15/20 of 100 m), but with constant deceleration the change in speed squared is what scales with distance. B assumes equal distance gives equal drop in speed, whereas equal distance actually gives equal drop in speed squared, so more than 100 m is needed from 15 m/s to reach zero. C treats speed drop per metre as constant (5 m/s per 100 m, so 15 m/s needs 300 m), but under uniform deceleration it is the drop in v^2 that is constant per metre. D uses the correct proportionality: over 100 m, v^2 drops by 400 − 225 = 175; to go from 15 m/s to rest requires a further drop of 225, so extra distance ≈ (225/175) × 100 ≈ 1.29 × 100 ≈ 130 m.