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A2 Daily A Level Physics question

2026-02-04 OCR A Wave optics II: double-slit interference; path difference & phase OCR-A Module 4: 4.4.2 Interference (Young’s double slit): superposition, path difference, fringe spacing proportionalities

In a lab double-slit experiment using a laser, the 5th bright fringe is 12 mm from the central maximum on a screen 2.0 m away. The slit separation is then reduced by 20%, with wavelength and screen distance unchanged. What is the new distance of the 5th bright fringe from the central maximum? Explain using how fringe position scales with slit separation.

  1. A 9.6 mm
  2. B 15 mm (correct)
  3. C 14.4 mm
  4. D 12 mm

Answer

The correct answer is B.

Correct: B — 15 mm. Fringe position for a given order scales inversely with slit separation, so reducing d by 20% (to 0.8d) makes the fringe distance larger by a factor 1/0.8 = 1.25; 12 mm × 1.25 = 15 mm. A assumes the distance scales directly with d (12 × 0.8 = 9.6 mm), which reverses the true dependence. B is correct as it applies the inverse proportionality, giving a 25% increase. C assumes only a 20% increase (12 × 1.2 = 14.4 mm), ignoring that the change is reciprocal, not additive. D suggests no change, overlooking that fringe spacing does depend on slit separation when wavelength and screen distance are fixed.